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Q.) If i - 3j + 5k bisects the angle between a and -i + 2j + 2k, where a is a unit vector, then
[A]a = (41i + 88j - 40k)/105
[B]a = (41i + 88j + 40k)/105
[C]a = (-41i - 88j - 40k)/105
[D]a = (41i -88j - 40k)/105